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7m^2-31m-20=0
a = 7; b = -31; c = -20;
Δ = b2-4ac
Δ = -312-4·7·(-20)
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1521}=39$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-39}{2*7}=\frac{-8}{14} =-4/7 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+39}{2*7}=\frac{70}{14} =5 $
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